4d^2+22d+30=0

Solution for 4d^2+22d+30=0 equation:

4d^2+22d+30=0

a = 4; b = 22; c = +30;
Δ = b2-4ac
Δ = 222-4·4·30
Δ = 4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$d_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$d_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{4}=2$
$d_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(22)-2}{2*4}=\frac{-24}{8}
=-3
$
$d_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(22)+2}{2*4}=\frac{-20}{8}
=-2+1/2
$